Problem 12.2 - Reactive Power Delivered to an Impedance Load
*
* Re-run the program for the circuit of Figure P12-1. Enter the
* initial current calculated for Problem 12-1.
*
* 1. Show the waveforms of the time-dependent voltage across the
* inductance and the current through the inductance. Does the
* current lead or lag the voltage? By how many degrees?
* 2. Graph the inductance voltage, V(2), and the expression for the
* reactive power waveform, I(L1)*V(2). For better definition of the
* waveform, change the x-axis range as instructed in the problem
* statement. Note that the reactive power has an average value of
* zero. This means that the energy delivered to the magnetic field
* of the inductance when the reactive power wave is positive is
* returned to the circuit (or "delivered to the circuit") when the
* reactive power waveform is negative. No real power is dissipated by
* an inductance.
* 3. On a PROBE graph of the time-dependent reactive power waveform,
* add the expression for the reactive power in this circuit:
* 500*SIN(45.57.3). Does the graph of this expression agree with
* your understanding of the meaning of reactive power (Q-power)?
* Note that the constant 57.3 in the expression above is used to
* convert the angle measure to radians, as is always required in
* PROBE graphs of trigonometric expressions.
*
.OPT NOPAGE NOBIAS
V1 1 0 SIN(0,100,60,0,0,135)
R1 1 2 7.0711
L1 2 0 18.756E-3 IC=??? ; Enter the initial inductance current.
.TRAN 2M .10 0 .5M UIC
.PROBE
.END